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Question: A car travels 60 miles in the same time that a car traveling 10 per hour faster travels 90 miles. What is the rate of each cars?
Find the indicated root or state that the expression is not a real number:
a. 3√ 8/125 This is the cube root of 8/125.
b. -4√81
Simplify each expression:
a. √45X^23
b. √ 96/3
Add or subtract as indicated:
a. 4√72 - 2√48
b. √75 - √48
Answers: A car travels 60 miles in the same time that a car traveling 10 per hour faster travels 90 miles. What is the rate of each cars?
Find the indicated root or state that the expression is not a real number:
a. 3√ 8/125 This is the cube root of 8/125.
b. -4√81
Simplify each expression:
a. √45X^23
b. √ 96/3
Add or subtract as indicated:
a. 4√72 - 2√48
b. √75 - √48
For the car question, use d=rt
Rate of first car =r, distance = 60, time = 60/r
Rate of 2nd car = r+10, distance 90, time = 90/(r+t)
Knowing the times are the same, we have the equation:
60/t = 90/(r+10), cross multiply to get:
60r + 600 = 90r
30r = 600
r = 20 mph = rate of first car
10 + 20 = 30 mph = rate of 2nd car
The cube root of 8/125 is 2/5.
-4(square root of 81) = -4x9 = -36
To simplify square roots, take out any "couples", meaning if there are 23 x's, there are 11 couples and one left over, so that'd be x^11(sqrt x). For the numbers under the radical, factor them completely and again, take out the couples.
To add or subtract, simplify first, and then add and subtract the like roots.
y r u posting ur homework in the joke/riddle section?
Oh - ok! I get it! Ha ha ha! You expect me to figure that out in the 'Jokes and Riddles section? You are TOO funny! Ha ha ha ha ha!!!