Amazing Riddle for the Wise?!


Question: An old farmer died and left 17 cows to his three sons. In his will, the farmer stated that his oldest son should get 1/2, his middle son should get 1/3, and his youngest son should get 1/9 of all the cows. The sons, who did not want to end up with half cows, sat for days trying to figure out how many cows each of them should get.
One day, their neighbour came by to see how they were doing after their father's death. The three sons told him their problem. After thinking for a while, the neighbour said: "I'll be right back!" He went away, and when he came back, the three sons could divide the cows according to their father's will, and in such a way that each of them got a whole number of cows.

what was the outcome?


Answers: An old farmer died and left 17 cows to his three sons. In his will, the farmer stated that his oldest son should get 1/2, his middle son should get 1/3, and his youngest son should get 1/9 of all the cows. The sons, who did not want to end up with half cows, sat for days trying to figure out how many cows each of them should get.
One day, their neighbour came by to see how they were doing after their father's death. The three sons told him their problem. After thinking for a while, the neighbour said: "I'll be right back!" He went away, and when he came back, the three sons could divide the cows according to their father's will, and in such a way that each of them got a whole number of cows.

what was the outcome?

it's not really possible because there's an odd # of cows
but, if the neighbor guy does bring a cow, there's 18------so, half of that is 9 for the oldest, a ninth is 2 for the youngest, and then 6 of that is 3 for the middle child-----------however, 9+2+6=17, so the neighbor just has to take his cow home

c'est impossible!

the answer is...................................69

Lots of steak to go around!

Maybe the neighbour gave them one of his own cows, so they started with 18, the first son gets 9, the second gets 6 and the third 2.

Wait a second, that only makes 17!! Oh man, I'm crap at this! :(





Bye!

He bred his bull with one of the cows, when the calf is born, there will be 18 and the math problem is solved!

"There is no spoon,,"

did they kill one and divided the meat?
Or maybe the neighbor brought a bull and the bull claimed a cow for his own. lol. I don't really know.

The neighbour lent them a cow so they started with 18 cows.
1/2 of 18 = 9
1/6 of 18 = 3
1/9 of 18 = 2
9 + 3 + 2 = 17 so they had one cow left over which was returned to the neighbour.

he gave them one cow

The neighbour borrowed an extra cow, to make the total number of cows 18. Then the oldest son got 1/2 of 18 is 9 cows, the middle son got 1/3 of 18 is 6 cows, and the youngest son got 1/9 of 18 is 2 cows. Since 9+6+2 = 17,the cows could be divided among the three brothers in such a way that the borrowed cow was left over, and could be returned to its owner.




first son = 9, second = 6, third = 2

The answer is 42

the neighbour came back with 1 cow total 18 cows.
18/2= 9 cows
18/3=6 cows
18/9=2 cows
total 17 cows
the neighbour thus divided the 17 cows and returned with his own

he took one for him self.



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