Can someone help me with this math problem.10 pts to anyone who explainsthe best!


Question: I am thinking of three different positive numbers.The greatest of them is twice a perfect square. The least of them is 1 less than half the greatest. The average of the three numbers is 12. Which three numbers am I thinking of???
plz show the work..............help!!!
plz explain it with the"x" method.That would be great


Answers: I am thinking of three different positive numbers.The greatest of them is twice a perfect square. The least of them is 1 less than half the greatest. The average of the three numbers is 12. Which three numbers am I thinking of???
plz show the work..............help!!!
plz explain it with the"x" method.That would be great

note: the 2 after X is square i.e. X*X

Let the highest number be 2X*X (twice a perfect square)
Then the lowest number will be 2X*X /2 – 1 = X2 – 1 (1 less than half the greatest)

Since the average of three numbers is 12, logically the highest number has to be greater than 12 and the lowest number has to be lesser than 12.

Therefore 2X*X > 12 and X*X – 1 < 12

Assuming X = 1; substituting in 2X*X = 2 which is not more than 12. so X cannot be 1

Assuming X = 2; substituting in 2X*X = 8 which is not more than 12. so X cannot be 2

Assuming X = 3; substituting in 2X*X = 18 which is more than 12. and also X*X – 1 = 8 which is less than 12. So X can be 3

Assuming X = 4; substituting in X*X– 1 = 15 which is more than 12. so X cannot be 4

Therefore X has to be 3

Therefore the highest number is 18 and the lowest number is 8

Average of three numbers is 12
That is (18+8+third number)/3 = 12

Therefore the third number = 10

Therefore the three numbers are 18, 10 and 8.

2, 3, 4

umm...



G= greatest,
A=average,
L=least.



L= {(1/2)G} - 1
A=12
G= square # x 2



um..... 9 is a square number.
9 x 2 = 18



would that be right for # 1?
{(1/2)18} - 1
= (9) - 1
= 8.
so yeah, that would work.



L = 8,

A = 12, and

G = 18.




hope this helped!

U should do ur homework bby urself



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