I have a semi-hard riddle.?!
Question: I have a semi-hard riddle!.!?
Two people went out fishing!. On the way home on of them said to the other "Give me one of your fish and we'll have the same amount!." and the other said, "No, no you give me one of your fish and I'll have twice as much as you!." How much did the each have!?!?Www@Enter-QA@Com
Answers:
one has 5 and the other has 7
if the one with 7 gives one they both have 6
if the one with 5 gives one they now have 4 and 8Www@Enter-QA@Com
if the one with 7 gives one they both have 6
if the one with 5 gives one they now have 4 and 8Www@Enter-QA@Com
0 & 2
If the first one caught no fish = 0
The second caught two =2
If the second gave 1 to the first: 0 + 1= 2-1=1=Same same!.
Now the second is asking the first to give one [which he has none] or the one he received from the second, the second will have 2 which is twice as the first!.
Clara!.!.!.!.!.open my beer, please!.!.!.!.I need to soak my brains!.Www@Enter-QA@Com
If the first one caught no fish = 0
The second caught two =2
If the second gave 1 to the first: 0 + 1= 2-1=1=Same same!.
Now the second is asking the first to give one [which he has none] or the one he received from the second, the second will have 2 which is twice as the first!.
Clara!.!.!.!.!.open my beer, please!.!.!.!.I need to soak my brains!.Www@Enter-QA@Com
its mathematically impossible:
a-1=b+1
n
b+1=2a
u'l get a= -1
n b= -3
n since both can't have negative numbers in fish
u can't get an answer!.!.hehe
okay!.!.okay!.!.i got it now
the first guy has 5 fish n the other 1 has 7
if the second guy gives 1 fish to the other both are left with 6 each(i!.e!., equal) n if the second guy gives one fish to the other then the first guy has 4 n the other has 8(i!.e, double)
hehe!.!.good one!Www@Enter-QA@Com
a-1=b+1
n
b+1=2a
u'l get a= -1
n b= -3
n since both can't have negative numbers in fish
u can't get an answer!.!.hehe
okay!.!.okay!.!.i got it now
the first guy has 5 fish n the other 1 has 7
if the second guy gives 1 fish to the other both are left with 6 each(i!.e!., equal) n if the second guy gives one fish to the other then the first guy has 4 n the other has 8(i!.e, double)
hehe!.!.good one!Www@Enter-QA@Com
just use this "complex algorithm":
person A= x
person B= x+2
"No, no you give me one of your fish and I'll have twice as much as you!."
[person A] 2(x-1) = (x+2)+1 [Person B]
2x - 2 = x + 3
x = 5
x+2= 7
so one guy had 5 fishes, while the other guy has 7 fishes!.
tadah!Www@Enter-QA@Com
person A= x
person B= x+2
"No, no you give me one of your fish and I'll have twice as much as you!."
[person A] 2(x-1) = (x+2)+1 [Person B]
2x - 2 = x + 3
x = 5
x+2= 7
so one guy had 5 fishes, while the other guy has 7 fishes!.
tadah!Www@Enter-QA@Com
three and five!. either this is a homework problem, or someone has changed their homework problem into a "riddle"
ack, i carried a number wrong!. Yes, it's 5 and 7!. That'll teach me to work it out without writing it down!.!.!.Www@Enter-QA@Com
ack, i carried a number wrong!. Yes, it's 5 and 7!. That'll teach me to work it out without writing it down!.!.!.Www@Enter-QA@Com
One person has 5 and the other person has 7!.Www@Enter-QA@Com
well um i do not think the question does not give enough info to answerWww@Enter-QA@Com
2 & 4!? (uhhhh)Www@Enter-QA@Com
am I think the first guy had 5 and the 2nd had 7Www@Enter-QA@Com
one!?Www@Enter-QA@Com
one and a halfWww@Enter-QA@Com
one!.!.!. i thinkWww@Enter-QA@Com
0!?Www@Enter-QA@Com
one person has 3 and the other has 1Www@Enter-QA@Com