Help Please? Just a quickie.?!


Question: Help Please!? Just a quickie!.!?
Alright guys!. I just need a little help solving for X!.

The question is!. -x+3y=-9

So I plug in 0 for y!.
(I'm suppose to)

Then I get left with!. -x =-9

So what do I do to get x !?!?!?

Help =]!.Www@Enter-QA@Com


Answers:
multiply both sides by -1
-1*-x = x
-1*-9=9

so x=9Www@Enter-QA@Com

You have the equation of a straight line!.
All points on the line will solve the equation!.
It crosses the X-axis at the point where x = 9!.
If you wanted a unique solution you would need another equation for another, different line!.
The point(s) where these two lines coincide (cross or touch) would be the graphical solution!.
The coordinates of that (or these) point(s) would be the numerical solution(s)!.
The solution of x = 9 is only true when y = 0!.Www@Enter-QA@Com

-x=-9 so multiply by -1
x=9Www@Enter-QA@Com

you multiply both sides by -1 making x=9Www@Enter-QA@Com

If -x = -9, the +x = +9

All you need to do is divide by -1Www@Enter-QA@Com

negatives on opposite sidez get cancelled!.!.!.so x=9!.!.!.!.!.omg! im smart!!.!.!.!.rite!?Www@Enter-QA@Com

Duh, if -x = -9 then x = 9Www@Enter-QA@Com



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