A man wishes to stay at a hotel...?!


Question: A man wishes to stay at a hotel!.!.!.!?
A man wishes to stay at a hotel for seven days!. He will be paying for his stay with golden rings!. He has seven golden rings: one by itself, two connected, and four connected!.

He must pay only one ring a day - one at a time!.

How does he pay!?Www@Enter-QA@Com


Answers:
"Mexican dude" is right, but not as thorough as he could be!. Sorry, dude!.

On day one, the man pays the single golden ring, telling the hotel manager not to sell any of the rings until his stay is over!. (He'll need them for change!.)

On day two, the man pays with the pair of rings, getting the single ring back as change!.

On day 3, the man pays with the single ring!. No change on day 3!.

On day 4, the man pays with the set of four rings, receiving the pair of rings and single ring for change!.

On day 5, the man pays with the single ring!. No change on day 5!.

On day 6, the man pays with the pair of rings, receiving the single ring for change!.

On day 7, the man pays with the single ring for the final time!.Www@Enter-QA@Com

he gives the single one the first day then lets the clerk hold one of the two rings that are connected for a day while he holds the other half till the next day and then hands it over then for the fourth and so on days the same thing!.!.!. applying the same rules to the four connected rings as the two connected rings :)


@ Lord ?dric Lambert:

i agree, i could have used more sophisticated words to express exactly what i was trying to say without saying too much!.!. but after entirely reading the "riddle" i wasn't sure if i was writing back to a teen or a kid!.!. i could have been more complete!.!. but i thought!.!. eh!.!.!.!.!.Www@Enter-QA@Com

day 1 pay them 1 ring (by itself)
day 2 pay them 2 rings (they give you back the ring of day 1)
day 3 pay them with the ring that they give you day 2
day 4 pay them with the 4 rings and they'll give you back 3 rings 1 by
itself and 2 connected
day 5 pay them with the ring itself ( that they gave you back day 4)
day 6 pay them with the 2 rings connected (that they gave you day 4,
they'll give you back the ring of day 5
day 7 pay them with the ring that they gave you back day 6!. Www@Enter-QA@Com

He pays with the single ring on the first day!. On the second he retrieves the single ring and pays with the double ring!. On the third day he gives the single ring back!. On the fourth day he retrieves the single and double rings and hands over the quadruple ring!. On the fifth day he gives the single ring!. On the sixth day he retrieves the single and gives the double!. And on the seventh day he hands over the single one more time, completing his stay!.Www@Enter-QA@Com

1st day he gives the single ring!
2nd day he gives the two connected rings and takes back the single ring!
3rd day he gives the single ring!
4th day he gives the four connected rings and takes back the two connected rings and the single ring!
5th day he gives the single ring!
6th day he gives the two connected rings and takes back the single ring!
7th day he gives the single ring!!!!.
Www@Enter-QA@Com

Not terribly difficult, bummer!.

day 1 = single ring
day 2 = double ring (trades for single)
day 3 = double ring, single ring!.
day 4 = 4 connected (gets back others)
day 5 = 4 connected, single
day 6 = 4 connected, double (gets back single)
day 7 = all rings

Edit: ouch you guys are quick! :)Www@Enter-QA@Com

He would take the two connected and the four connected rings and disconnect them!. He then pays one ring a day for seven days!.Www@Enter-QA@Com



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